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CUET PG MCA Previous Year Questions (PYQs)

CUET PG MCA Quantitative Aptitude PYQ

CUET PG MCA PYQ
A sum of money doubles itself on simple interest in 10 years. Find the rate of interest per annum.





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CUET PG MCA Previous Year PYQCUET PG MCA CUET 2023 PYQ

Solution

CUET PG MCA PYQ
The area of a rhombus is 120 $cm^2$ and length of its one diagonal in 24 cm. Find the perimeter of the rhombus (in cm)





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CUET PG MCA Previous Year PYQCUET PG MCA CUET 2023 PYQ

Solution

CUET PG MCA PYQ
The monthly income and expenditure of a person were Rs.10,000 and Rs. 6,000 respectively. Next year, his income increased by 15% and his expenditure increased by 8%. Then the percentage increase in his savings is:





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CUET PG MCA Previous Year PYQCUET PG MCA CUET 2023 PYQ

Solution

CUET PG MCA PYQ
In a class, 4/5 of the students are boys and rest are girls. If 2/5 of the boys and 1/4 of girls are absent, what part of the total number of students is present?





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CUET PG MCA Previous Year PYQCUET PG MCA CUET 2024 PYQ

Solution

Solution

Given: 4/5 of the students are boys, and the rest are girls. 2/5 of boys and 1/4 of girls are absent.

Step-by-Step Solution

  • Total students = N
  • Boys: (4/5) × N = 4N/5
  • Girls: (1/5) × N = N/5
  • Boys absent: (2/5) × (4N/5) = 8N/25
  • Girls absent: (1/4) × (N/5) = N/20
  • Boys present: (4N/5 - 8N/25 = 12N/25)
  • Girls present: (N/5 - N/20 = 3N/20)
  • Total present = (12N/25 + 3N/20)

Final Calculation

LCM of 25 and 20 is 100:
(12N/25 = 48N/100), (3N/20 = 15N/100)
Total present = (48N/100 + 15N/100 = 63N/100)

Answer: 63/100

CUET PG MCA PYQ
If 2 cats catch 2 mice in 2 minutes, how many cats are needed to catch 18 mice in 18 minutes?





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CUET PG MCA Quantitative Aptitude PYQCUET PG MCA Time and Work PYQ

Solution

By the formula 
$\frac{M_1 H_1 D_1}{W_1}$=$\frac{M_2 H_2 D_2}{W_2}$ ----(i)

Here 
$M_1=2, H_1=2, W_1=2$
$M_2=?, H_2=18, W_2=18$ 

Using (i)
$\frac{2 \times 2 \times 1}{2}$=$\frac{M_2 \times 18 }{18}$
$M_2=2$
Hence, 2 cats are needed to catch 18 mice.

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